One String No Trouble - HackerEarth Solution


Math Greedy

Python Code:

t = input()
count = 0
for i in range(len(t)-1):
    if t[i]==t[i+1]:
        continue
    else:
        count+=1
print(count+1)


Comments

Submit
0 Comments
More Questions

779. K-th Symbol in Grammar
701. Insert into a Binary Search Tree
429. N-ary Tree Level Order Traversal
739. Daily Temperatures
647. Palindromic Substrings
583. Delete Operation for Two Strings
518. Coin Change 2
516. Longest Palindromic Subsequence
468. Validate IP Address
450. Delete Node in a BST
445. Add Two Numbers II
442. Find All Duplicates in an Array
437. Path Sum III
436. Find Right Interval
435. Non-overlapping Intervals
406. Queue Reconstruction by Height
380. Insert Delete GetRandom O(1)
332. Reconstruct Itinerary
368. Largest Divisible Subset
377. Combination Sum IV
322. Coin Change
307. Range Sum Query - Mutable
287. Find the Duplicate Number
279. Perfect Squares
275. H-Index II
274. H-Index
260. Single Number III
240. Search a 2D Matrix II
238. Product of Array Except Self
229. Majority Element II